Difference between revisions of "2006 AIME I Problems/Problem 7"
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== See also == | == See also == | ||
+ | * [[2006 AIME I Problems/Problem 6 | Previous problem]] | ||
+ | * [[2006 AIME I Problems/Problem 8 | Next problem]] | ||
* [[2006 AIME I Problems]] | * [[2006 AIME I Problems]] | ||
[[Category:Intermediate Geometry Problems]] | [[Category:Intermediate Geometry Problems]] |
Revision as of 20:41, 11 March 2007
Problem
An angle is drawn on a set of equally spaced parallel lines as shown. The ratio of the area of shaded region to the area of shaded region
is 11/5. Find the ratio of shaded region
to the area of shaded region
Solution
Apex of the angle is not on the parallel lines.
Let...
- The set of parallel lines...
- be perpendicular to x-axis
- & cross x-axis at 0, 1, 2...
- Base of region
be at
; bigger base of region
at
- One side of the angle be x-axis.
- The other side be
Then...
As area of triangle =.5 base x height...
By similar method, seems to be 408.