Difference between revisions of "1976 AHSME Problems/Problem 24"
MRENTHUSIASM (talk | contribs) |
MRENTHUSIASM (talk | contribs) |
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/* Made by Klaus-Anton, Edited by MRENTHUSIASM */ | /* Made by Klaus-Anton, Edited by MRENTHUSIASM */ | ||
size(200); | size(200); | ||
− | pair K=(0,0),B=(1,0),A=(-1,0),L=(0,0.5),M=(sqrt(2)/2,.25), | + | pair K=(0,0),B=(1,0),A=(-1,0),L=(0,0.5),M=(sqrt(2)/2,.25),I=(2*sqrt(2)/3,1/3),E=(sqrt(2)/3,1/3); |
draw(circle(K,1)^^A--B); | draw(circle(K,1)^^A--B); | ||
draw(circle(L,0.5)^^circle(M,.25)); | draw(circle(L,0.5)^^circle(M,.25)); | ||
Line 35: | Line 35: | ||
dot(L,linewidth(4)); | dot(L,linewidth(4)); | ||
dot(M,linewidth(4)); | dot(M,linewidth(4)); | ||
− | dot( | + | dot(I,linewidth(4)); |
</asy> | </asy> | ||
Revision as of 06:37, 6 September 2021
Problem
In the adjoining figure, circle has diameter
; circle
is tangent to circle
and to
at the center of circle
; and circle
tangent to circle
, to circle
and
. The ratio of the area of circle
to the area of circle
is
Solution
Let and
be the radii of circles
and
respectively.
See Also
1976 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.