Difference between revisions of "2006 Cyprus MO/Lyceum/Problem 4"

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==Problem==
 
==Problem==
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Given the function <math>f(x)=\alpha x^2 +9x+ \frac{81}{4\alpha}</math> , <math>\alpha \neq 0</math>
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Which of the following is correct, about the graph of <math>f</math>?
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A. intersects x-axis
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B. touches y-axis
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C. touches x-axis
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D. has minimum point
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E. has maximum point
  
 
==Solution==
 
==Solution==
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<math>\alpha x^2 + 9x + \frac{81}{4\alpha} = \left(\sqrt{\alpha}x + \frac{9}{2\sqrt{\alpha}}\right)^2</math>. Notice that if <math>f(x) = 0</math>, then <math>x</math> has the unique root of <math>-\frac{\frac{9}{2\sqrt{\alpha}}}{\sqrt{\alpha}} = \frac{-9}{2\alpha}</math>, so it touches the x-axis, <math>\mathrm{(C)}</math>.
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From above, <math>\mathrm{(A)}</math> is not correct because the graph does not intersect with the x-axis (it is tangent to it). <math>\mathrm{(B)}</math> is not true; the graph intersects with the y-axis, since the [[parabola]] opens up or down. <math>\mathrm{(D)}</math> and <math>\mathrm{(E)}</math> depend upon the value of <math>\alpha</math>; if <math>\alpha > 0</math>, then the parabola has a minimum, and if <math>\alpha > 0</math> then the parabola has a maximum.
  
 
==See also==
 
==See also==
 
{{CYMO box|year=2006|l=Lyceum|num-b=3|num-a=5}}
 
{{CYMO box|year=2006|l=Lyceum|num-b=3|num-a=5}}
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[[Category:Introductory Algebra Problems]]

Revision as of 20:10, 17 October 2007

Problem

Given the function $f(x)=\alpha x^2 +9x+ \frac{81}{4\alpha}$ , $\alpha \neq 0$ Which of the following is correct, about the graph of $f$?

A. intersects x-axis

B. touches y-axis

C. touches x-axis

D. has minimum point

E. has maximum point

Solution

$\alpha x^2 + 9x + \frac{81}{4\alpha} = \left(\sqrt{\alpha}x + \frac{9}{2\sqrt{\alpha}}\right)^2$. Notice that if $f(x) = 0$, then $x$ has the unique root of $-\frac{\frac{9}{2\sqrt{\alpha}}}{\sqrt{\alpha}} = \frac{-9}{2\alpha}$, so it touches the x-axis, $\mathrm{(C)}$.

From above, $\mathrm{(A)}$ is not correct because the graph does not intersect with the x-axis (it is tangent to it). $\mathrm{(B)}$ is not true; the graph intersects with the y-axis, since the parabola opens up or down. $\mathrm{(D)}$ and $\mathrm{(E)}$ depend upon the value of $\alpha$; if $\alpha > 0$, then the parabola has a minimum, and if $\alpha > 0$ then the parabola has a maximum.

See also

2006 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 3
Followed by
Problem 5
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