Difference between revisions of "2001 AMC 8 Problems/Problem 5"

(Solution 2)
(Solution 2)
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==Solution 2==
 
==Solution 2==
 
Since we are estimating, we can make <math>1088</math> become <math>1000</math>, and <math>5280</math> will become <math>5000</math>. Then do <math> \frac{5000}{1000} </math> and we get 5, or <math>\boxed{\text{C}} </math>
 
Since we are estimating, we can make <math>1088</math> become <math>1000</math>, and <math>5280</math> will become <math>5000</math>. Then do <math> \frac{5000}{1000} </math> and we get 5, or <math>\boxed{\text{C}} </math>
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 +
~Trex226
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2001|num-b=4|num-a=6}}
 
{{AMC8 box|year=2001|num-b=4|num-a=6}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:17, 2 January 2023

Problem

On a dark and stormy night Snoopy suddenly saw a flash of lightning. Ten seconds later he heard the sound of thunder. The speed of sound is 1088 feet per second and one mile is 5280 feet. Estimate, to the nearest half-mile, how far Snoopy was from the flash of lightning.

$\text{(A)}\ 1 \qquad \text{(B)}\ 1\frac{1}{2} \qquad \text{(C)}\ 2 \qquad \text{(D)}\ 2\frac{1}{2} \qquad \text{(E)}\ 3$

Solution

During the $10$ seconds, the sound traveled $1088\times10=10880$ feet from the lightning to Snoopy. This is equivalent to $\frac{10880}{5280}\approx2$ miles, $\boxed{\text{C}}$.

Solution 2

Since we are estimating, we can make $1088$ become $1000$, and $5280$ will become $5000$. Then do $\frac{5000}{1000}$ and we get 5, or $\boxed{\text{C}}$

~Trex226

See Also

2001 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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