Difference between revisions of "2006 AMC 12B Problems/Problem 4"
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== Solution == | == Solution == | ||
− | The total price of the items is <math>(8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18. | + | The total price of the items is <math>(8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18.95</math> |
− | <math>20-18.05= | + | <math>20-18.95=1.05</math> |
+ | |||
+ | <math>\frac{1.05}{20}=.0525 \Rightarrow \text{(A)}</math> | ||
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== See also == | == See also == | ||
{{AMC12 box|year=2006|ab=B|num-b=3|num-a=5}} | {{AMC12 box|year=2006|ab=B|num-b=3|num-a=5}} |
Revision as of 10:03, 3 December 2007
Problem
Mary is about to pay for five items at the grocery store. The prices of the items are , , , , and . Mary will pay with a twenty-dollar bill. Which of the following is closest to the percentage of the that she will receive in change?
Solution
The total price of the items is
See also
2006 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 3 |
Followed by Problem 5 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |