Difference between revisions of "2003 AMC 12B Problems/Problem 1"

Revision as of 09:06, 5 February 2008

Which of the following is the same as

$\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}$ ?

$\text {(A) } -1 \qquad \text {(B) } -\frac{2}{3} \qquad \text {(C) } \frac{2}{3} \qquad \text {(D) } 1 \qquad \text {(E) } \frac{14}{3}$

$2-4+6-8+10-12+14=-2-2-2+14=8$

$3-6+9-12+15-18+21=-3-3-3+21=12$

$\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}=\frac{8}{12}=\frac{2}{3} \Rightarrow \text {(C)}$

2003 AMC 12B (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
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All AMC 12 Problems and Solutions

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	==See also==		==See also==
		+	{{AMC12 box\|year=2003\|ab=B\|before=First Question\|num-a=2}}