Difference between revisions of "1995 AHSME Problems/Problem 3"

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== Problem ==
 
== Problem ==
The total in-store price for an appliance is <math>\</math><math>99.99</math>. A television commercial advertises the same product for three easy payments of <math>\</math><math>29.98</math> and a one-time shipping and handling charge of <math>\</math><math>9.98</math>. How many cents are saved by buying the appliance from the television advertiser?
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The total in-store price for an appliance is <math>&#036;</math>99.99<math>. A television commercial advertises the same product for three easy payments of </math>&#036;<math>29.98</math> and a one-time shipping and handling charge of <math>&#036;</math>9.98<math>. How many cents are saved by buying the appliance from the television advertiser?
  
<math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }  </math>
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</math> \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 }  <math>
  
== Solution ==
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== Solution 1==
<math>99.99 - (29.98*3 + 9.98) = 99.99 - 99.92 = .07 \Rightarrow \mathrm{(B)}</math>
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</math>99.99 - (29.98*3 + 9.98) = 99.99 - 99.92 = .07 \Rightarrow \mathrm{(B)}<math>
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==Solution 2==
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Alternately, the in-store price is </math>1<math> cent below </math>100.00<math> dollars.
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The television price is </math>3\cdot 2 + 2 = 8<math> cents below </math>30.00 \cddot 3 + 10.00 = 100.00<math> dollars.
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Therefore, the difference is </math>8 - 1 = 7<math> cents, and the answer is </math>\mathrm{(B)}$
  
 
== See also ==
 
== See also ==

Revision as of 23:58, 17 August 2011

Problem

The total in-store price for an appliance is $&#036;$99.99$. A television commercial advertises the same product for three easy payments of$$$29.98$ and a one-time shipping and handling charge of $&#036;$9.98$. How many cents are saved by buying the appliance from the television advertiser?$ \mathrm{(A) \ 6 } \qquad \mathrm{(B) \ 7 } \qquad \mathrm{(C) \ 8 } \qquad \mathrm{(D) \ 9 } \qquad \mathrm{(E) \ 10 } $== Solution 1==$99.99 - (29.98*3 + 9.98) = 99.99 - 99.92 = .07 \Rightarrow \mathrm{(B)}$==Solution 2==

Alternately, the in-store price is$ (Error compiling LaTeX. Unknown error_msg)1$cent below$100.00$dollars.

The television price is$ (Error compiling LaTeX. Unknown error_msg)3\cdot 2 + 2 = 8$cents below$30.00 \cddot 3 + 10.00 = 100.00$dollars.

Therefore, the difference is$ (Error compiling LaTeX. Unknown error_msg)8 - 1 = 7$cents, and the answer is$\mathrm{(B)}$

See also

1995 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions