Difference between revisions of "Cauchy-Schwarz Inequality"
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There are many ways to prove this; one of the more well-known is to consider the equation | There are many ways to prove this; one of the more well-known is to consider the equation | ||
− | <math>(a_1x+b_1)^2+(a_2x+b_2)^2+...+(a_nx+b_n)^2=0</math>. | + | <math>(a_1x+b_1)^2+(a_2x+b_2)^2+...+(a_nx+b_n)^2=0</math>. Expanding, we find the equation to be of the form <math>Ax^2+Bx+C</math>, where <math>A=\sum_{i=1}^n a_i^2</math>, <math>B=2\sum_{j=1}^n a_jb_j</math>, and <math>C=\sum_{k=1}^n b_k^2.</math>. By the [[Trivial inequality | Trivial Inequality]], we know that the left-hand-side of the original equation is always at least 0, so either both roots are [[Complex Numbers]], or there is a double root at <math>x=0</math>. Either way, the [[discriminant]] of the equation is nonpositive. Taking the [[discriminant]], <math>B^2-4AC \leq 0</math> and substituting the above values of A, B, and C leaves us with the '''Cauchy-Schwarz Inequality''', <math>(a_1b_1+a_2b_2+...+a_nb_n)^2 \leq (a_1^2+a_2^2+...+a_n^2)(b_1^2+b_2^2+...+b_n^2)</math>, |
+ | or, in the more compact [[sigma notation]], | ||
+ | <math>\left(\sum a_ib_i\right)</math> <math>\leq \left(\sum a_i^2\right)\left(\sum b_i^2\right)</math> | ||
+ | |||
+ | Note that this also gives us the equality case; equality holds if and only if the discriminant is equal to 0, which is true if and only if the equation has 0 as a double root, which is true if and only if <math>\frac{a_1}{b_1}=\frac{a_2}{b_2}=...=\frac{a_n}{b_n}</math>. | ||
This inequality is used very frequently to solve Olympiad-level Inequality problems, such as those on the [[United States of America Mathematics Olympiad | USAMO]] and [[International Mathematics Olympiad | IMO]]. | This inequality is used very frequently to solve Olympiad-level Inequality problems, such as those on the [[United States of America Mathematics Olympiad | USAMO]] and [[International Mathematics Olympiad | IMO]]. |
Revision as of 01:08, 18 June 2006
The Cauchy-Schwarz Inequality (which is known by other names, including Cauchy's Inequality) states that, for two sets of real numbers and
, the following inequality is always true:
Equality holds if and only if .
There are many ways to prove this; one of the more well-known is to consider the equation
. Expanding, we find the equation to be of the form
, where
,
, and
. By the Trivial Inequality, we know that the left-hand-side of the original equation is always at least 0, so either both roots are Complex Numbers, or there is a double root at
. Either way, the discriminant of the equation is nonpositive. Taking the discriminant,
and substituting the above values of A, B, and C leaves us with the Cauchy-Schwarz Inequality,
,
or, in the more compact sigma notation,
Note that this also gives us the equality case; equality holds if and only if the discriminant is equal to 0, which is true if and only if the equation has 0 as a double root, which is true if and only if .
This inequality is used very frequently to solve Olympiad-level Inequality problems, such as those on the USAMO and IMO.