Difference between revisions of "2008 AMC 10B Problems/Problem 22"
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==Problem== | ==Problem== | ||
− | + | Three red beads, two white beads, and one blue bead are placed in line in random order. What is the probability that no two neighboring beads are the same color? | |
+ | |||
+ | A) 1/12 B) 1/10 C) 1/6 D) 1/3 E) 1/2 | ||
==Solution== | ==Solution== | ||
− | + | ||
+ | C) 1/6 | ||
==See also== | ==See also== | ||
{{AMC10 box|year=2008|ab=B|num-b=21|num-a=23}} | {{AMC10 box|year=2008|ab=B|num-b=21|num-a=23}} |
Revision as of 11:13, 4 January 2009
Problem
Three red beads, two white beads, and one blue bead are placed in line in random order. What is the probability that no two neighboring beads are the same color?
A) 1/12 B) 1/10 C) 1/6 D) 1/3 E) 1/2
Solution
C) 1/6
See also
2008 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 21 |
Followed by Problem 23 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |