Difference between revisions of "2010 AMC 12B Problems/Problem 5"
(Created page with '== Problem 5 == Lucky Larry's teacher asked him to substitute numbers for <math>a</math>, <math>b</math>, <math>c</math>, <math>d</math>, and <math>e</math> in the expression <ma…') |
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| Line 9: | Line 9: | ||
<cmath>-8 + e = -2 - e</cmath> | <cmath>-8 + e = -2 - e</cmath> | ||
<cmath>2e = 6</cmath> | <cmath>2e = 6</cmath> | ||
| − | <cmath>e = 3 | + | <cmath>e = 3 \;\;(D)</cmath> |
| − | + | ||
== See also == | == See also == | ||
{{AMC12 box|year=2010|num-b=12|num-a=14|ab=B}} | {{AMC12 box|year=2010|num-b=12|num-a=14|ab=B}} | ||
Revision as of 17:46, 9 July 2010
Problem 5
Lucky Larry's teacher asked him to substitute numbers for 
, 
, 
, 
, and 
in the expression 
and evaluate the result. Larry ignored the parenthese but added and subtracted correctly and obtained the correct result by coincidence. The number Larry sustitued for , , , and were 
, 
, 
, and 
, respectively. What number did Larry substitude for ?
Solution
We simply plug in the numbers
![\[1 - 2 - 3 - 4 + e = 1 - (2 - (3 - (4 + e)))\]](http://latex.artofproblemsolving.com/7/a/4/7a45109237a44425ac1f654e545592212c0e8d24.png)
![\[-8 + e = -2 - e\]](http://latex.artofproblemsolving.com/6/4/0/6404d113e89d63c3e63dc55c338e718f1b906f27.png)
![\[2e = 6\]](http://latex.artofproblemsolving.com/f/5/4/f5474d53aa43904dd17b97dc61e0d5e8d8c333fb.png)
![\[e = 3 \;\;(D)\]](http://latex.artofproblemsolving.com/3/0/b/30b7a727bd9caf1881ba760eb4c0986ba4c340b4.png)
See also
| 2010 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 12 |
Followed by Problem 14 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
