Difference between revisions of "2010 AMC 10B Problems/Problem 3"
m (see also, box) |
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<math> | <math> | ||
− | \ | + | \textbf{(A)}\ 3 |
\qquad | \qquad | ||
− | \ | + | \textbf{(B)}\ 4 |
\qquad | \qquad | ||
− | \ | + | \textbf{(C)}\ 5 |
\qquad | \qquad | ||
− | \ | + | \textbf{(D)}\ 8 |
\qquad | \qquad | ||
− | \ | + | \textbf{(E)}\ 9 |
</math> | </math> | ||
== Solution == | == Solution == | ||
− | After you draw <math>4</math> socks, you can have one of each color, so (according to the pigeonhole principle), if you pull <math>\boxed{\ | + | After you draw <math>4</math> socks, you can have one of each color, so (according to the [[pigeonhole principle]]), if you pull <math>\boxed{\textbf{(C)}\ 5}</math> then you will be guaranteed a matching pair. |
+ | |||
+ | ==See Also== | ||
+ | {{AMC10 box|year=2010|ab=B|num-b=2|num-a=4}} |
Revision as of 23:51, 25 November 2011
Problem
A drawer contains red, green, blue, and white socks with at least 2 of each color. What is the minimum number of socks that must be pulled from the drawer to guarantee a matching pair?
Solution
After you draw socks, you can have one of each color, so (according to the pigeonhole principle), if you pull then you will be guaranteed a matching pair.
See Also
2010 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |