Difference between revisions of "2011 AMC 10B Problems/Problem 5"
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Revision as of 13:11, 4 July 2013
Problem
In multiplying two positive integers and
, Ron reversed the digits of the two-digit number
. His erroneous product was
. What is the correct value of the product of
and
?
Solution
Since the was the erroneous product of two integers, one that had two digits, the two factors have to be
and
. Reverse the digits of the two-digit number so that
is
. Find the product of
and
.
See Also
2011 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.