Difference between revisions of "2010 AMC 10A Problems/Problem 3"

Revision as of 10:57, 4 July 2013

Problem 3

Tyrone had $97$ marbles and Eric had $11$ marbles. Tyrone then gave some of his marbles to Eric so that Tyrone ended with twice as many marbles as Eric. How many marbles did Tyrone give to Eric?

$\mathrm{(A)}\ 3 \qquad \mathrm{(B)}\ 13 \qquad \mathrm{(C)}\ 18 \qquad \mathrm{(D)}\ 25 \qquad \mathrm{(E)}\ 29$

Solution

Let $x$ be the number of marbles Tyrone gave to Eric. Then, $97-x = 2\cdot(11+x)$ . Solving for $x$ yields $75=3x$ and $x = 25$ . The answer is $\boxed{D}$ .

2010 AMC 10A (Problems • Answer Key • Resources)
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Difference between revisions of "2010 AMC 10A Problems/Problem 3"

Revision as of 10:57, 4 July 2013

Problem 3

Solution

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