Difference between revisions of "1950 AHSME Problems/Problem 3"

Revision as of 10:57, 5 July 2013

The sum of the roots of the equation $4x^{2}+5-8x=0$ is equal to:

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ -5\qquad\textbf{(C)}\ -\frac{5}{4}\qquad\textbf{(D)}\ -2\qquad\textbf{(E)}\ \text{None of these}$

We can divide by 4 to get: $x^{2}-2x+\dfrac{5}{4}=0.$

Using Vieta's formulas, we find that the roots add to $2$ or $\boxed{\textbf{(E)}\ \text{None of these}}$ .

1950 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50
All AHSME Problems and Solutions

Revision as of 04:39, 23 April 2012 (view source) 1=2 (talk \| contribs) m (aHSME box --> AHSME 50p box) ← Older edit		Revision as of 10:57, 5 July 2013 (view source) Nathan wailes (talk \| contribs) Newer edit →
Line 16:		Line 16:

	[[Category:Introductory Algebra Problems]]		[[Category:Introductory Algebra Problems]]
		+	{{MAA Notice}}