Difference between revisions of "1950 AHSME Problems/Problem 3"
Rocknroll9 (talk | contribs) (→Solution) |
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<math> x^{2}-2x+\dfrac{5}{4}=0.</math> | <math> x^{2}-2x+\dfrac{5}{4}=0.</math> | ||
− | Using Vieta's | + | The Vieta's formula states that in quadratic equation ax^2+bx+c, the sum of the roots of the equation is -b/a. |
+ | Using Vieta's formula, we find that the roots add to <math>2</math> or <math>\boxed{\textbf{(E)}\ \text{None of these}}</math>. | ||
==See Also== | ==See Also== |
Revision as of 02:12, 24 December 2017
Problem
The sum of the roots of the equation is equal to:
Solution
We can divide by 4 to get:
The Vieta's formula states that in quadratic equation ax^2+bx+c, the sum of the roots of the equation is -b/a.
Using Vieta's formula, we find that the roots add to or
.
See Also
1950 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
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All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.