Difference between revisions of "1968 AHSME Problems/Problem 3"

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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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<math>\fbox{A}</math>
  
 
== See also ==
 
== See also ==

Revision as of 02:26, 29 September 2014

Problem

A straight line passing through the point $(0,4)$ is perpendicular to the line $x-3y-7=0$. Its equation is:

$\text{(A) } y+3x-4=0\quad \text{(B) } y+3x+4=0\quad \text{(C) } y-3x-4=0\quad \\ \text{(D) } 3y+x-12=0\quad \text{(E) } 3y-x-12=0$

Solution

$\fbox{A}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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