Difference between revisions of "1968 AHSME Problems/Problem 15"

(Created page with "== Problem == Let <math>P</math> be the product of any three consecutive positive odd integers. The largest integer dividing all such <math>P</math> is: <math>\text{(A) } 15\qu...")
 
m (Solution)
Line 10: Line 10:
  
 
== Solution ==
 
== Solution ==
<math>\fbox{}</math>
+
<math>\fbox{D}</math>
  
 
== See also ==
 
== See also ==

Revision as of 02:30, 29 September 2014

Problem

Let $P$ be the product of any three consecutive positive odd integers. The largest integer dividing all such $P$ is:

$\text{(A) } 15\quad \text{(B) } 6\quad \text{(C) } 5\quad \text{(D) } 3\quad \text{(E) } 1$

Solution

$\fbox{D}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png