Difference between revisions of "Mock AIME 5 2005-2006 Problems/Problem 4"

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== Problem ==
 
== Problem ==
 
Let <math>m</math> and <math>n</math> be integers such that <math>1 < m \le 10</math> and <math>m < n \le 100</math>. Given that <math>x = \log_m{n}</math> and <math>y = \log_n{m}</math>, find the number of ordered pairs <math>(m,n)</math> such that <math>\lfloor x \rfloor = \lceil y \rceil</math>. (<math>\lfloor a \rfloor</math> is the greatest integer less than or equal to <math>a</math> and <math>\lceil a \rceil</math> is the least integer greater than or equal to <math>a</math>).
 
Let <math>m</math> and <math>n</math> be integers such that <math>1 < m \le 10</math> and <math>m < n \le 100</math>. Given that <math>x = \log_m{n}</math> and <math>y = \log_n{m}</math>, find the number of ordered pairs <math>(m,n)</math> such that <math>\lfloor x \rfloor = \lceil y \rceil</math>. (<math>\lfloor a \rfloor</math> is the greatest integer less than or equal to <math>a</math> and <math>\lceil a \rceil</math> is the least integer greater than or equal to <math>a</math>).
 
== Solution ==
 
  
 
== Solution ==
 
== Solution ==

Latest revision as of 19:41, 22 March 2016

Problem

Let $m$ and $n$ be integers such that $1 < m \le 10$ and $m < n \le 100$. Given that $x = \log_m{n}$ and $y = \log_n{m}$, find the number of ordered pairs $(m,n)$ such that $\lfloor x \rfloor = \lceil y \rceil$. ($\lfloor a \rfloor$ is the greatest integer less than or equal to $a$ and $\lceil a \rceil$ is the least integer greater than or equal to $a$).

Solution

See also

Mock AIME 5 2005-2006 (Problems, Source)
Preceded by
Problem 3
Followed by
Problem 5
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