Difference between revisions of "2014 AMC 8 Problems/Problem 17"
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| − | George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first <math>\frac{1}{2}</math> mile at a speed of only 2 miles per hour. At how many miles per hour must George run the last <math>\frac{1}{2}</math> mile in order to arrive just as school begins today? | + | George walks <math>1</math> mile to school. He leaves home at the same time each day, walks at a steady speed of <math>3</math> miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first <math>\frac{1}{2}</math> mile at a speed of only <math>2</math> miles per hour. At how many miles per hour must George run the last <math>\frac{1}{2}</math> mile in order to arrive just as school begins today? |
<math>\textbf{(A) }4\qquad\textbf{(B) }6\qquad\textbf{(C) }8\qquad\textbf{(D) }10\qquad \textbf{(E) }12</math> | <math>\textbf{(A) }4\qquad\textbf{(B) }6\qquad\textbf{(C) }8\qquad\textbf{(D) }10\qquad \textbf{(E) }12</math> | ||
Revision as of 19:15, 26 November 2014
George walks 
mile to school. He leaves home at the same time each day, walks at a steady speed of 
miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first 
mile at a speed of only 
miles per hour. At how many miles per hour must George run the last mile in order to arrive just as school begins today?
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 16 |
Followed by Problem 18 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
