Difference between revisions of "1968 AHSME Problems/Problem 4"
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<math>4 \star 4 \star 4 = 4 \star 2 = \frac{4}{3}</math> | <math>4 \star 4 \star 4 = 4 \star 2 = \frac{4}{3}</math> | ||
− | <math>\fbox{C}</math> | + | |
+ | Therefore, our answer is <math>\fbox{C}</math> | ||
+ | |||
+ | Solution by VivekA | ||
== See also == | == See also == |
Revision as of 12:43, 28 July 2016
Problem
Define an operation for positive real numbers as . Then equals:
Solution
Therefore, our answer is
Solution by VivekA
See also
1968 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.