Difference between revisions of "1959 AHSME Problems/Problem 3"

(Added Problem, Solution, and See Also)
 
m (category)
Line 4: Line 4:
  
 
==Solution==
 
==Solution==
Note that a kite has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is <math>\boxed{\textbf{E}}</math>
+
Note that a kite has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is <math>\boxed{\textbf{E}}</math>.
  
 
==See also==
 
==See also==
 
{{AHSME 50p box|year=1959|num-b=2|num-a=4}}
 
{{AHSME 50p box|year=1959|num-b=2|num-a=4}}
 
{{MAA Notice}}
 
{{MAA Notice}}
 +
[[Category:Introductory Geometry Problems]]

Revision as of 10:59, 21 July 2024

Problem 3

If the diagonals of a quadrilateral are perpendicular to each other, the figure would always be included under the general classification: $\textbf{(A)}\ \text{rhombus} \qquad\textbf{(B)}\ \text{rectangles} \qquad\textbf{(C)}\ \text{square} \qquad\textbf{(D)}\ \text{isosceles trapezoid}\qquad\textbf{(E)}\ \text{none of these}$

Solution

Note that a kite has perpendicular diagonals, but is not a subcategory of any of the existing answer choices. Therefore, the answer is $\boxed{\textbf{E}}$.

See also

1959 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png