Difference between revisions of "1950 AHSME Problems/Problem 34"
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==Solution 2== | ==Solution 2== | ||
− | The radii of the | + | The radii of the circles are <math>\frac{20}{2\pi}</math> and <math>\frac{25}{2\pi}</math>, respectively. The positive difference is therefore <math>\boxed{\textbf{(D)}\ \dfrac{5}{2\pi}\text{ in}}</math>. |
==See Also== | ==See Also== |
Revision as of 20:59, 20 March 2018
Contents
Problem
When the circumference of a toy balloon is increased from inches to
inches, the radius is increased by:
Solution
When the circumference of a circle is increased by a percentage, the radius is also increased by the same percentage (or else the ratio of the circumference to the diameter wouldn't be anymore)
We see that the circumference was increased by
. This means the radius was also increased by
. The radius of the original balloon is
. With the
increase, it becomes
. The increase is
Solution 2
The radii of the circles are and
, respectively. The positive difference is therefore
.
See Also
1950 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 33 |
Followed by Problem 35 | |
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