Difference between revisions of "2001 AMC 8 Problems/Problem 10"
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==Problem== | ==Problem== | ||
| − | Bob Bluster, the KNEWS meteorologist, determined that the mathematical odds of <math>\emph{no rain}</math> tomorrow are 11:9. What would a mathematics student determine | + | Bob Bluster, the KNEWS meteorologist, determined that the mathematical odds of <math>\emph{no rain}</math> tomorrow are 11:9. What would a mathematics student determine acdzscsdcs the percent chance there <math>\emph{will be rain}</math> tomorrow? |
==Solution== | ==Solution== | ||
Revision as of 11:53, 26 October 2018
Problem
Bob Bluster, the KNEWS meteorologist, determined that the mathematical odds of 
tomorrow are 11:9. What would a mathematics student determine acdzscsdcs the percent chance there 
tomorrow?
Solution
is equivalent to 
. Therefore, of a number is the same as 
times that number. 
quarters is 
dollar, so Bryden will get 
dollars, 
.
See Also
| 2001 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
