Difference between revisions of "1953 AHSME Problems/Problem 46"
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so the answer is <math>\boxed{\textbf{(D)}\ \frac{3}{4}}</math>. | so the answer is <math>\boxed{\textbf{(D)}\ \frac{3}{4}}</math>. | ||
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Latest revision as of 00:11, 4 January 2019
Problem 46
Instead of walking along two adjacent sides of a rectangular field, a boy took a shortcut along the diagonal of the field and saved a distance equal to the longer side. The ratio of the shorter side of the rectangle to the longer side was:
Solution
Let be the sides of the rectangle. The length of the diagonal is , and the length of the two adjacent sides is . Then the distance the boy saves is . Setting this equal to , we have so the answer is .
See Also
1953 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 45 |
Followed by Problem 47 | |
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