Difference between revisions of "2014 AMC 8 Problems/Problem 1"

Revision as of 09:18, 10 November 2019

lol

We have $H=8-7=1$ and $T=8-2+5=11$ . Clearly $1-11=-10$ , so our answer is $\boxed{\textbf{(A)}-10}$ .

2014 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
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All AJHSME/AMC 8 Problems and Solutions

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-==Problem==
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-Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry’s answer is <math>H</math> and Terry’s answer is <math>T</math>, what is <math>H-T</math>?
-<math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math>
 ==Solution==