Difference between revisions of "2016 AMC 10A Problems/Problem 1"
Karthic7073 (talk | contribs) m (→See Also) |
(→Solution 1) |
||
Line 7: | Line 7: | ||
==Solution 1== | ==Solution 1== | ||
− | + | <math>\frac{11!-10!}{9!}=\frac{11\cdot10!-10!}{9!}=\frac{100\cdot9!}{9!}=100</math> | |
+ | <math>B</math> | ||
==Solution 2== | ==Solution 2== |
Revision as of 18:28, 26 January 2020
Contents
[hide]Problem
What is the value of ?
Solution 1
Solution 2
We can use subtraction of fractions to get
Solution 3
Factoring out gives .
See Also
2016 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2016 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by First Problem |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.