Difference between revisions of "2005 AMC 8 Problems/Problem 1"
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==Problem== | ==Problem== | ||
| − | Connie multiplies a number by 2 and gets 60 as her answer. However, she should | + | Connie multiplies a number by <math>2</math> and gets <math>60</math> as her answer. However, she should have divided the number by <math>2</math> to get the correct answer. What is the correct answer? |
| − | have divided the number by 2 to get the correct answer. What is the correct | ||
| − | answer? | ||
<math> \textbf{(A)}\ 7.5\qquad\textbf{(B)}\ 15\qquad\textbf{(C)}\ 30\qquad\textbf{(D)}\ 120\qquad\textbf{(E)}\ 240 </math> | <math> \textbf{(A)}\ 7.5\qquad\textbf{(B)}\ 15\qquad\textbf{(C)}\ 30\qquad\textbf{(D)}\ 120\qquad\textbf{(E)}\ 240 </math> | ||
Revision as of 21:06, 11 February 2020
Problem
Connie multiplies a number by 
and gets 
as her answer. However, she should have divided the number by to get the correct answer. What is the correct answer?
Solution
If 
is the number, then 
and 
. Dividing the number by yields 
.
See Also
| 2005 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
