Difference between revisions of "2020 AIME II Problems"
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==Problem 1== | ==Problem 1== | ||
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+ | Find the number of ordered pairs of positive integers <math>(m,n)</math> such that <math>{m^2n = 20 ^{20}}</math>. | ||
[[2020 AIME II Problems/Problem 1 | Solution]] | [[2020 AIME II Problems/Problem 1 | Solution]] | ||
==Problem 2== | ==Problem 2== | ||
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+ | Let <math>P</math> be a point chosen uniformly at random in the interior of the unit square with vertices at <math>(0,0), (1,0), (1,1)</math>, and <math>(0,1)</math>. The probability that the slope of the line determined by <math>P</math> and the point <math>\left(\frac58, \frac38 \right)</math> is greater than <math>\frac12</math> can be written as <math>\frac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m+n</math>. | ||
[[2020 AIME II Problems/Problem 2 | Solution]] | [[2020 AIME II Problems/Problem 2 | Solution]] | ||
==Problem 3== | ==Problem 3== | ||
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+ | The value of <math>x</math> that satisfies <math>\log_{2^x} 3^{20} = \log_{2^{x+3}} 3^{2020}</math> can be written as <math>\frac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m+n</math>. | ||
[[2020 AIME II Problems/Problem 3 | Solution]] | [[2020 AIME II Problems/Problem 3 | Solution]] | ||
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==Problem 5== | ==Problem 5== | ||
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+ | For each positive integer <math>n</math>, left <math>f(n)</math> be the sum of the digits in the base-four representation of <math>n</math> and let <math>g(n)</math> be the sum of the digits in the base-eight representation of <math>f(n)</math>. For example, <math>f(2020) = f(133210_{\text{four}}) = 10 = 12_{\text{eight}}</math>, and <math>g(2020) = \text{the digit sum of }12_{\text{eight}} = 3</math>. Let <math>N</math> be the least value of <math>n</math> such that the base-sixteen representation of <math>g(n)</math> cannot be expressed using only the digits <math>0</math> through <math>9</math>. Find the remainder when <math>N</math> is divided by <math>1000</math>. | ||
[[2020 AIME II Problems/Problem 5 | Solution]] | [[2020 AIME II Problems/Problem 5 | Solution]] | ||
==Problem 6== | ==Problem 6== | ||
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+ | Define a sequence recursively by <math>t_1 = 20</math>, <math>t_2 = 21</math>, and<cmath>t_n = \frac{5t_{n-1}+1}{25t_{n-2}}</cmath>for all <math>n \ge 3</math>. Then <math>t_{2020}</math> can be written as <math>\frac{p}{q}</math>, where <math>p</math> and <math>q</math> are relatively prime positive integers. Find <math>p+q</math>. | ||
[[2020 AIME II Problems/Problem 6 | Solution]] | [[2020 AIME II Problems/Problem 6 | Solution]] | ||
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==Problem 10== | ==Problem 10== | ||
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+ | Find the sum of all positive integers <math>n</math> such that when <math>1^3+2^3+3^3+\cdots +n^3</math> is divided by <math>n+5</math>, the remainder is <math>17</math>. | ||
[[2020 AIME II Problems/Problem 10 | Solution]] | [[2020 AIME II Problems/Problem 10 | Solution]] | ||
==Problem 11== | ==Problem 11== | ||
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+ | Let <math>P(X) = x^2 - 3x - 7</math>, and let <math>Q(x)</math> and <math>R(x)</math> be two quadratic polynomials also with the coefficient of <math>x^2</math> equal to <math>1</math>. David computes each of the three sums <math>P + Q</math>, <math>P + R</math>, and <math>Q + R</math> and is surprised to find that each pair of these sums has a common root, and these three common roots are distinct. If <math>Q(0) = 2</math>, then <math>R(0) = \frac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m + n</math>. | ||
[[2020 AIME II Problems/Problem 11 | Solution]] | [[2020 AIME II Problems/Problem 11 | Solution]] | ||
==Problem 12== | ==Problem 12== | ||
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+ | Let <math>m</math> and <math>n</math> be odd integers greater than <math>1.</math> An <math>m\times n</math> rectangle is made up of unit squares where the squares in the top row are numbered left to right with the integers <math>1</math> through <math>n</math>, those in the second row are numbered left to right with the integers <math>n + 1</math> through <math>2n</math>, and so on. Square <math>200</math> is in the top row, and square <math>2000</math> is in the bottom row. Find the number of ordered pairs <math>(m,n)</math> of odd integers greater than <math>1</math> with the property that, in the <math>m\times n</math> rectangle, the line through the centers of squares <math>200</math> and <math>2000</math> intersects the interior of square <math>1099</math>. | ||
[[2020 AIME II Problems/Problem 12 | Solution]] | [[2020 AIME II Problems/Problem 12 | Solution]] | ||
==Problem 13== | ==Problem 13== | ||
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+ | Convex pentagon <math>ABCDE</math> has side lengths <math>AB=5</math>, <math>BC=CD=DE=6</math>, and <math>EA=7</math>. Moreover, the pentagon has an inscribed circle (a circle tangent to each side of the pentagon). Find the area of <math>ABCDE</math>. | ||
[[2020 AIME II Problems/Problem 13 | Solution]] | [[2020 AIME II Problems/Problem 13 | Solution]] | ||
==Problem 14== | ==Problem 14== | ||
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+ | For real number <math>x</math> let <math>\lfloor x\rfloor</math> be the greatest integer less than or equal to <math>x</math>, and define <math>\{x\} = x - \lfloor x \rfloor</math> to be the fractional part of <math>x</math>. For example, <math>\{3\} = 0</math> and <math>\{4.56\} = 0.56</math>. Define <math>f(x)=x\{x\}</math>, and let <math>N</math> be the number of real-valued solutions to the equation <math>f(f(f(x)))=17</math> for <math>0\leq x\leq 2020</math>. Find the remainder when <math>N</math> is divided by <math>1000</math>. | ||
[[2020 AIME II Problems/Problem 14 | Solution]] | [[2020 AIME II Problems/Problem 14 | Solution]] | ||
==Problem 15== | ==Problem 15== | ||
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+ | Let <math>\triangle ABC</math> be an acute scalene triangle with circumcircle <math>\omega</math>. The tangents to <math>\omega</math> at <math>B</math> and <math>C</math> intersect at <math>T</math>. Let <math>X</math> and <math>Y</math> be the projections of <math>T</math> onto lines <math>AB</math> and <math>AC</math>, respectively. Suppose <math>BT = CT = 16</math>, <math>BC = 22</math>, and <math>TX^2 + TY^2 + XY^2 = 1143</math>. Find <math>XY^2</math>. | ||
[[2020 AIME II Problems/Problem 15 | Solution]] | [[2020 AIME II Problems/Problem 15 | Solution]] |
Revision as of 01:09, 8 June 2020
2020 AIME II (Answer Key) | AoPS Contest Collections • PDF | ||
Instructions
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1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 |
Contents
[hide]Problem 1
Find the number of ordered pairs of positive integers such that .
Problem 2
Let be a point chosen uniformly at random in the interior of the unit square with vertices at , and . The probability that the slope of the line determined by and the point is greater than can be written as , where and are relatively prime positive integers. Find .
Problem 3
The value of that satisfies can be written as , where and are relatively prime positive integers. Find .
Problem 4
Problem 5
For each positive integer , left be the sum of the digits in the base-four representation of and let be the sum of the digits in the base-eight representation of . For example, , and . Let be the least value of such that the base-sixteen representation of cannot be expressed using only the digits through . Find the remainder when is divided by .
Problem 6
Define a sequence recursively by , , andfor all . Then can be written as , where and are relatively prime positive integers. Find .
Problem 7
Problem 8
Problem 9
Problem 10
Find the sum of all positive integers such that when is divided by , the remainder is .
Problem 11
Let , and let and be two quadratic polynomials also with the coefficient of equal to . David computes each of the three sums , , and and is surprised to find that each pair of these sums has a common root, and these three common roots are distinct. If , then , where and are relatively prime positive integers. Find .
Problem 12
Let and be odd integers greater than An rectangle is made up of unit squares where the squares in the top row are numbered left to right with the integers through , those in the second row are numbered left to right with the integers through , and so on. Square is in the top row, and square is in the bottom row. Find the number of ordered pairs of odd integers greater than with the property that, in the rectangle, the line through the centers of squares and intersects the interior of square .
Problem 13
Convex pentagon has side lengths , , and . Moreover, the pentagon has an inscribed circle (a circle tangent to each side of the pentagon). Find the area of .
Problem 14
For real number let be the greatest integer less than or equal to , and define to be the fractional part of . For example, and . Define , and let be the number of real-valued solutions to the equation for . Find the remainder when is divided by .
Problem 15
Let be an acute scalene triangle with circumcircle . The tangents to at and intersect at . Let and be the projections of onto lines and , respectively. Suppose , , and . Find .
2020 AIME II (Problems • Answer Key • Resources) | ||
Preceded by 2020 AIME I Problems |
Followed by 2021 AIME I Problems | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.