Difference between revisions of "2020 AMC 8 Problems/Problem 14"
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The average is given to be <math>4750</math>. This is because the dotted line is halfway in between <math>4500</math> and <math>5000</math>. There are <math>20</math> cities, so our answer is simply <cmath>4750\cdot20=95000==>\boxed{\textbf{(D) }95000}</cmath> | The average is given to be <math>4750</math>. This is because the dotted line is halfway in between <math>4500</math> and <math>5000</math>. There are <math>20</math> cities, so our answer is simply <cmath>4750\cdot20=95000==>\boxed{\textbf{(D) }95000}</cmath> | ||
− | ==See also== {{AMC8 box|year=2020| | + | ==See also== {{AMC8 box|year=2020|num-a=13|num-a=15}} {{MAA Notice}} |
Revision as of 00:21, 18 November 2020
Problem 14
There are cities in the County of Newton. Their populations are shown in the bar chart below. The average population of all the cities is indicated by the horizontal dashed line. Which of the following is closest to the total population of all cities?
Solution 1
The average is given to be . This is because the dotted line is halfway in between and . There are cities, so our answer is simply
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by [[2020 AMC 8 Problems/Problem {{{num-b}}}|Problem {{{num-b}}}]] |
Followed by Problem 15 | |
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All AJHSME/AMC 8 Problems and Solutions |
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