Difference between revisions of "2020 AMC 8 Problems/Problem 15"
Icematrix2 (talk | contribs) |
|||
Line 1: | Line 1: | ||
− | |||
Suppose <math>15\%</math> of <math>x</math> equals <math>20\%</math> of <math>y.</math> What percentage of <math>x</math> is <math>y?</math> | Suppose <math>15\%</math> of <math>x</math> equals <math>20\%</math> of <math>y.</math> What percentage of <math>x</math> is <math>y?</math> | ||
Line 5: | Line 4: | ||
==Solution 1== | ==Solution 1== | ||
− | + | Multiply by <math>5</math> to get <math>0.75x=y</math>. The <math>0.75</math> here can be converted to <math>75\%</math>. Therefore, <math>\boxed{\textbf{C}}</math> is the answer. | |
− | ==See also== | + | ==See also== |
{{AMC8 box|year=2020|num-b=14|num-a=16}} | {{AMC8 box|year=2020|num-b=14|num-a=16}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 00:22, 18 November 2020
Suppose of equals of What percentage of is
Solution 1
Multiply by to get . The here can be converted to . Therefore, is the answer.
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.