Difference between revisions of "2020 AMC 8 Problems/Problem 5"
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==Solution 3== | ==Solution 3== | ||
− | Assume that the pitcher has a total capacity of <math>100</math> ounces. Since it is filled three fourths with pineapple juice, it contains <math>75</math> ounces of pineapple juice, which means that each cup will contain <math>\frac{75}{5}=15</math> ounces of pineapple juice. Since the total capacity of the pitcher was <math>100</math> ounces, it follows that each cup received <math>15\%</math> of the total capacity of the pitcher, yielding <math>\boxed{\textbf{(C) }15}</math> | + | Assume that the pitcher has a total capacity of <math>100</math> ounces. Since it is filled three fourths with pineapple juice, it contains <math>75</math> ounces of pineapple juice, which means that each cup will contain <math>\frac{75}{5}=15</math> ounces of pineapple juice. Since the total capacity of the pitcher was <math>100</math> ounces, it follows that each cup received <math>15\%</math> of the total capacity of the pitcher, yielding <math>\boxed{\textbf{(C) }15}</math>. |
==Video Solution== | ==Video Solution== |
Revision as of 06:15, 20 November 2020
Problem
Three fourths of a pitcher is filled with pineapple juice. The pitcher is emptied by pouring an equal amount of juice into each of cups. What percent of the total capacity of the pitcher did each cup receive?
Solution 1
Each cup is filled with of the amount of juice in the pitcher, so the answer is .
Solution 2
The pitcher is full, i.e. full. Therefore each cup receives of the total capacity, so the answer is .
Solution 3
Assume that the pitcher has a total capacity of ounces. Since it is filled three fourths with pineapple juice, it contains ounces of pineapple juice, which means that each cup will contain ounces of pineapple juice. Since the total capacity of the pitcher was ounces, it follows that each cup received of the total capacity of the pitcher, yielding .
Video Solution
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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