Difference between revisions of "2014 AMC 8 Problems/Problem 8"

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==Solution==
 
==Solution==
The only 3-digit number that is divisible by 11 and has a units digit of 2 is 132 so A is \boxed{\textbf{(D)}~3}$.
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The only 3-digit number that is divisible by 11 and has a units digit of 2 is 132 so A is 3 so our answer is (D).
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2014|num-b=7|num-a=9}}
 
{{AMC8 box|year=2014|num-b=7|num-a=9}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 11:50, 27 November 2020

Problem

Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at their math club meeting. They paid their guest speaker $\textdollar\underline{1} \underline{A} \underline{2}$. What is the missing digit $A$ of this $3$-digit number?

$\textbf{(A) }0\qquad\textbf{(B) }1\qquad\textbf{(C) }2\qquad\textbf{(D) }3\qquad \textbf{(E) }4$

Solution

The only 3-digit number that is divisible by 11 and has a units digit of 2 is 132 so A is 3 so our answer is (D).

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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