Difference between revisions of "2020 AMC 10A Problems/Problem 3"
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== Solution 2 == | == Solution 2 == | ||
− | Substituting values for < | + | Substituting values for <math>a, b,\text{ and } c</math>, we see that if each of them satify the inequalities above, the value goes to be <math>-1</math>. |
Therefore, the product of the given fraction equals <math>(-1)(-1)(-1)=\boxed{\textbf{(A)}-1}</math>. | Therefore, the product of the given fraction equals <math>(-1)(-1)(-1)=\boxed{\textbf{(A)}-1}</math>. | ||
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~CoolJupiter | ~CoolJupiter | ||
− | + | == Video Solution 1 == | |
https://youtu.be/WUcbVNy2uv0 | https://youtu.be/WUcbVNy2uv0 | ||
~IceMatrix | ~IceMatrix | ||
− | + | == Video Solution 2 == | |
https://youtu.be/Nrdxe4UAqkA | https://youtu.be/Nrdxe4UAqkA | ||
Line 30: | Line 30: | ||
Education, The Study of Everything | Education, The Study of Everything | ||
− | + | == Video Solution 3 == | |
https://www.youtube.com/watch?v=7-3sl1pSojc | https://www.youtube.com/watch?v=7-3sl1pSojc | ||
~bobthefam | ~bobthefam | ||
− | + | == Video Solution 4 == | |
https://youtu.be/ZccL6yKrTiU | https://youtu.be/ZccL6yKrTiU | ||
Revision as of 13:28, 22 December 2020
Contents
Problem
Assuming , , and , what is the value in simplest form of the following expression?
Solution 1
Note that is times . Likewise, is times and is times . Therefore, the product of the given fraction equals .
Solution 2
Substituting values for , we see that if each of them satify the inequalities above, the value goes to be . Therefore, the product of the given fraction equals .
Solution 3
It is known that for . We use this fact to cancel out the terms.
~CoolJupiter
Video Solution 1
~IceMatrix
Video Solution 2
Education, The Study of Everything
Video Solution 3
https://www.youtube.com/watch?v=7-3sl1pSojc
~bobthefam
Video Solution 4
~savannahsolver
See Also
2020 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.