Difference between revisions of "1956 AHSME Problems/Problem 42"
Coolmath34 (talk | contribs) (Created page with "== Problem 42== The equation <math>\sqrt {x + 4} - \sqrt {x - 3} + 1 = 0</math> has: <math>\textbf{(A)}\ \text{no root} \qquad \textbf{(B)}\ \text{one real root} \ \text...") |
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<cmath>x + 4 = x - 3 -2\sqrt{x-3} + 1</cmath> | <cmath>x + 4 = x - 3 -2\sqrt{x-3} + 1</cmath> | ||
<cmath>6 = -2\sqrt{x-3}</cmath> | <cmath>6 = -2\sqrt{x-3}</cmath> | ||
− | We don't need to solve any further. The square root term is negative, therefore there will be no real roots. The answer is <math>\boxed{ | + | We don't need to solve any further. The square root term is negative, therefore there will be no real roots. The answer is <math>\boxed{D}.</math> |
-coolmath34 | -coolmath34 |
Revision as of 03:58, 8 March 2021
Problem 42
The equation has:
Solution
Simplify. We don't need to solve any further. The square root term is negative, therefore there will be no real roots. The answer is
-coolmath34
See Also
1956 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 41 |
Followed by Problem 43 | |
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All AHSME Problems and Solutions |
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