Difference between revisions of "2014 AMC 8 Problems/Problem 1"
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==Problem== | ==Problem== | ||
| − | Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry’s answer is <math>H</math> and Terry’s answer is <math>T</math>, what | + | Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry’s answer is <math>H</math> and Terry’s answer is <math>T</math>, what's <math>H-T</math>? |
<math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | <math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | ||
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==Solution== | ==Solution== | ||
Revision as of 11:56, 11 June 2021
Problem
Harry and Terry are each told to calculate 
. Harry gets the correct answer. Terry ignores the parentheses and calculates 
. If Harry’s answer is 
and Terry’s answer is 
, what's 
?
Solution
We have 
and 
. Clearly 
, so our answer is 
.
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
