Difference between revisions of "2021 Fall AMC 10A Problems/Problem 16"
MRENTHUSIASM (talk | contribs) m (Undo revision 167038 by MRENTHUSIASM (talk)) (Tag: Undo) |
MRENTHUSIASM (talk | contribs) m (→Solution 1 (Graphing)) |
||
Line 217: | Line 217: | ||
drawLabelAxes(); | drawLabelAxes(); | ||
− | draw((- | + | draw((-10,0)--(10,0),mediumblue+linewidth(1.25),"$y=|\lfloor x \rfloor|$"); |
for (int i = 0; i > -10; --i) { | for (int i = 0; i > -10; --i) { | ||
dot((i,-1),mediumblue+linewidth(4)); | dot((i,-1),mediumblue+linewidth(4)); | ||
Line 225: | Line 225: | ||
} | } | ||
for (int i = -9; i < 10; ++i) { | for (int i = -9; i < 10; ++i) { | ||
− | + | dot((i,0),mediumblue+linewidth(0.7),UnFill); | |
} | } | ||
</asy> | </asy> |
Revision as of 22:19, 29 November 2021
Contents
Problem
The graph of is symmetric about which of the following? (Here is the greatest integer not exceeding .)
Solution 1 (Graphing)
Let and Note that the graph of is a reflection of the graph of about the -axis, followed by a translation of unit right.
The graph of is shown below: The graph of is shown below: The graph of is shown below:
Therefore, the graph of is symmetric about
~MRENTHUSIASM
Solution 2 (Casework)
For all and note that:
- and
We rewrite as We apply casework to the value of
- and
- and
- and
It follows that
It follows that
It follows that
It follows that
It follows that
It follows that
Together, we have so the graph of is symmetric about
Alternatively, we can eliminate and once we finish with Case 3. This leaves us with
~MRENTHUSIASM
Solution 3 (Casework)
Denote , where and . Hence, is the integer part of and is the decimal part of .
: .
We have
: .
We have
Therefore, the graph of is symmetric through the point .
Therefore, the answer is .
~Steven Chen (www.professorchenedu.com)
See Also
2021 Fall AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.