Difference between revisions of "2017 AMC 10A Problems/Problem 3"
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Erics son07 (talk | contribs) (→Solution 2 (probably much less efficient than solution 1)) |
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The short vertical walkways have an area of <math>2 ft^{2}</math> each, and there are <math>9</math> of them <math>\longrightarrow 18 ft^{2}</math>. | The short vertical walkways have an area of <math>2 ft^{2}</math> each, and there are <math>9</math> of them <math>\longrightarrow 18 ft^{2}</math>. | ||
− | Adding the areas together, we have | + | Adding the areas together, we have <math>60 ft^{2} + 18 ft^{2} = 78 ft^{2} \Longrightarrow \boxed{\textbf{(B)}\ 78}</math>. |
~JH. L | ~JH. L | ||
Latest revision as of 23:41, 13 June 2022
Contents
Problem
Tamara has three rows of two -feet by
-feet flower beds in her garden. The beds are separated and also surrounded by
-foot-wide walkways, as shown on the diagram. What is the total area of the walkways, in square feet?
Solution
Finding the area of the shaded walkway can be achieved by computing the total area of Tamara's garden and then subtracting the combined area of her six flower beds.
Since the width of Tamara's garden contains three margins, the total width is feet.
Similarly, the height of Tamara's garden is feet.
Therefore, the total area of the garden is square feet.
Finally, since the six flower beds each have an area of square feet, the area we seek is
, and our answer is
Solution 2 (probably much less efficient than solution 1)
The long horizontal walkways have an area of each, and there are
of them
.
The short vertical walkways have an area of each, and there are
of them
.
Adding the areas together, we have .
~JH. L
Video Solution
~savannahsolver
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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