Difference between revisions of "2006 Cyprus MO/Lyceum/Problem 3"

Revision as of 21:13, 17 October 2007

The domain of the function $f(x)=\sqrt{4+2x}$ is

A. $(-2,+\infty)$

B. $[0,+\infty)$

C. $[-2,+\infty)$

D. $[-2,0]$

E. $R$

2x+4 must be non-negative. Therefore, x+2 must be non-negative. Therefore, all x greater than or equal to -2 are in the domain. $\mathrm {(A)}$

@@ Line 1: / Line 1: @@
 ==Problem==
-{{empty}}
+The domain of the function <math>f(x)=\sqrt{4+2x}</math> is
+A. <math>(-2,+\infty)</math>
+B. <math>[0,+\infty)</math>
+C.  <math>[-2,+\infty)</math>
+D. <math>[-2,0]</math>
+E. <math>R</math>
 ==Solution==
-{{solution}}
+x+4 must be non-negative. Therefore, x+2 must be non-negative. Therefore, all x greater than or equal to -2 are in the domain. <math>\mathrm {(A)}</math>
 ==See also==
 {{CYMO box|year=2006|l=Lyceum|num-b=2|num-a=4}}