Difference between revisions of "1984 AIME Problems/Problem 8"

Revision as of 08:36, 18 October 2007

Problem

The equation $z^6+z^3+1$ has complex roots with argument $\theta$ between $90^\circ$ and $180^\circ$ in thet complex plane. Determine the degree measure of $\theta$ .

Solution

If $r$ is a root of $z^6+z^3+1$ , then $0=(r^3-1)(r^6+r^3+1)=r^9-1$ . The polynomial $x^9-1$ has all of its roots with absolute value 1 and argument of the form $40m^\circ$ for integer $m$ .

This reduces $\theta$ to either 120 or 160. But $\theta$ can't be 120 because if $r=\cos 120^\circ +i\sin 120^\circ$ , then $r^3=1$ and $r^6+r^3+1=3$ , a contradiction. This leaves $\theta=160$ .

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 * [[Mathematics competition resources]]
-[[Category:Trigonometry Problems]]
+[[Category:Intermediate Trigonometry Problems]]
+[[Category:Intermediate Complex Numbers Problems]]

1984 AIME (Problems • Answer Key • Resources)
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Difference between revisions of "1984 AIME Problems/Problem 8"

Revision as of 08:36, 18 October 2007

Problem

Solution

See also