Difference between revisions of "2014 AMC 8 Problems/Problem 3"
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<math>\textbf{(A) }240\qquad\textbf{(B) }250\qquad\textbf{(C) }260\qquad\textbf{(D) }270\qquad \textbf{(E) }280</math> | <math>\textbf{(A) }240\qquad\textbf{(B) }250\qquad\textbf{(C) }260\qquad\textbf{(D) }270\qquad \textbf{(E) }280</math> | ||
==Solution== | ==Solution== | ||
− | Isabella read <math>3\cdot 36+3\cdot 44</math> pages in the first 6 days. Although this can be calculated directly, it is simpler to calculate it as <math>3\cdot (36+44)=3\cdot 80</math>, which gives that she read <math>240</math> pages. | + | Isabella read <math>3\cdot 36+3\cdot 44</math> pages in the first 6 days. Although this can be calculated directly, it is simpler to calculate it as <math>3\cdot (36+44)=3\cdot 80</math>, which gives that she read <math>240</math> pages. On her last day, she read <math>10</math> more pages for a total of <math>240+10=\boxed{\textbf{(B)}~250}</math> pages. |
==Video Solution== | ==Video Solution== |
Revision as of 02:54, 24 December 2022
Contents
Problem
Isabella had a week to read a book for a school assignment. She read an average of pages per day for the first three days and an average of
pages per day for the next three days. She then finished the book by reading
pages on the last day. How many pages were in the book?
Solution
Isabella read pages in the first 6 days. Although this can be calculated directly, it is simpler to calculate it as
, which gives that she read
pages. On her last day, she read
more pages for a total of
pages.
Video Solution
~savannahsolver
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.