Difference between revisions of "2001 AMC 8 Problems/Problem 10"
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==Solution 2== | ==Solution 2== | ||
| − | Since <math> 2000\% </math> is just <math>\frac{2000}{100}</math>, we can multiply that by <math>100</math>, because four quarters is a <math>100</math> cents. After the multiplication, we get <math>2000</math>. Since our answer is in cents right now, we need to convert it to dollars, which would be <math>\boxed{\text{(A) 20}}</math> | + | Since <math> 2000\% </math> is just <math>\frac{2000}{100}</math>, we can multiply that by <math>100</math>, because four quarters is a <math>100</math> cents. After the multiplication, we get <math>2000</math>. Since our answer is in cents right now, we need to convert it to dollars, which would be <math>\boxed{\text{(A) 20}}</math> dollars. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2001|num-b=9|num-a=11}} | {{AMC8 box|year=2001|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 20:41, 10 January 2023
Contents
Problem
A collector offers to buy state quarters for 2000% of their face value. At that rate how much will Bryden get for his four state quarters?
Solution
is equivalent to 
. Therefore, of a number is the same as 
times that number. 
quarters is 
dollar, so Bryden will get 
dollars, 
.
Solution 2
Since is just 
, we can multiply that by 
, because four quarters is a cents. After the multiplication, we get 
. Since our answer is in cents right now, we need to convert it to dollars, which would be 
dollars.
See Also
| 2001 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
