Difference between revisions of "2023 AMC 8 Problems/Problem 13"

(Made the variable definition clearer, and reformatted the solution.)
(Asy replaces png.)
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finish lines. The <math>3</math>rd water station is located <math>2</math> miles after the <math>1</math>st repair station. How long is the race
 
finish lines. The <math>3</math>rd water station is located <math>2</math> miles after the <math>1</math>st repair station. How long is the race
 
in miles?
 
in miles?
[[File:2023 AMC 8-13.png|center|500px]]
+
 
 +
<asy>
 +
//Diagram By TheMathGuyd, The road is widened for bicycle safety
 +
size(10cm);
 +
real tl = 0.2;
 +
real dpth = 0.8;
 +
fill((0,0)--(8,0)--(8,1)--(0,1)--cycle,mediumgrey);
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draw((0,.5)--(8,.5),dashed+white);
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draw((0,0)--(8,0)--(8,1)--(0,1)--cycle,black);
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draw((1,0)--(1,-tl));
 +
draw((2,0)--(2,-tl));
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draw((7,0)--(7,-tl));
 +
label(rotate(45)*"Water 1",(0.6,-dpth));
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label(rotate(45)*"Water 2",(1.6,-dpth));
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label(rotate(45)*"Water 7",(6.6,-dpth));
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label("\ldots\ldots",(4.2,-dpth));
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label(rotate(90)*"Start",(0,0.5),W);
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label(rotate(-90)*"Finish",(8,0.5),E);
 +
//Someone is going to see this and find out I don't know how to put borders on text and laugh.
 +
real lh = 0.45;
 +
real lr = 0.1;
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path bx = (-lh,-lr)--(0,-lr)--(0,1+lr)--(-lh,1+lr)--cycle;
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draw(bx);
 +
draw(reflect((4,0),(4,1))*bx);
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</asy>
 +
 
 
<math>\textbf{(A)}\ 8 \qquad \textbf{(B)}\ 16 \qquad \textbf{(C)}\ 24 \qquad \textbf{(D)}\ 48 \qquad \textbf{(E)}\ 96</math>
 
<math>\textbf{(A)}\ 8 \qquad \textbf{(B)}\ 16 \qquad \textbf{(C)}\ 24 \qquad \textbf{(D)}\ 48 \qquad \textbf{(E)}\ 96</math>
  

Revision as of 11:55, 26 January 2023

Problem

Along the route of a bicycle race, $7$ water stations are evenly spaced between the start and finish lines, as shown in the figure below. There are also $2$ repair stations evenly spaced between the start and finish lines. The $3$rd water station is located $2$ miles after the $1$st repair station. How long is the race in miles?

[asy] //Diagram By TheMathGuyd, The road is widened for bicycle safety size(10cm); real tl = 0.2; real dpth = 0.8; fill((0,0)--(8,0)--(8,1)--(0,1)--cycle,mediumgrey); draw((0,.5)--(8,.5),dashed+white); draw((0,0)--(8,0)--(8,1)--(0,1)--cycle,black); draw((1,0)--(1,-tl)); draw((2,0)--(2,-tl)); draw((7,0)--(7,-tl)); label(rotate(45)*"Water 1",(0.6,-dpth)); label(rotate(45)*"Water 2",(1.6,-dpth)); label(rotate(45)*"Water 7",(6.6,-dpth)); label("\ldots\ldots",(4.2,-dpth)); label(rotate(90)*"Start",(0,0.5),W); label(rotate(-90)*"Finish",(8,0.5),E); //Someone is going to see this and find out I don't know how to put borders on text and laugh. real lh = 0.45; real lr = 0.1; path bx = (-lh,-lr)--(0,-lr)--(0,1+lr)--(-lh,1+lr)--cycle; draw(bx); draw(reflect((4,0),(4,1))*bx); [/asy]

$\textbf{(A)}\ 8 \qquad \textbf{(B)}\ 16 \qquad \textbf{(C)}\ 24 \qquad \textbf{(D)}\ 48 \qquad \textbf{(E)}\ 96$

Solution

Suppose that the race is $d$ miles long. The water stations are located at \[\frac{d}{8}, \frac{2d}{8}, \ldots, \frac{7d}{8}\] miles from the start, and the repair stations are located at \[\frac{d}{3}, \frac{2d}{3}\] miles from the start.

We are given that $\frac{3d}{8}=\frac{d}{3}+2,$ from which \begin{align*} \frac{9d}{24}&=\frac{8d}{24}+2 \\ \frac{d}{24}&=2 \\ d&=\boxed{\textbf{(D)}\ 48}. \end{align*} ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM

Video Solution (Animated)

https://youtu.be/NivfOThj1No

~Star League (https://starleague.us)

Video Solution by Magic Square

https://youtu.be/-N46BeEKaCQ?t=4439

See Also

2023 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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