Difference between revisions of "2023 AMC 8 Problems/Problem 3"
MRENTHUSIASM (talk | contribs) (→Solution: Removed contributor who did not really contribute.) |
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==Video Solution by SpreadTheMathLove== | ==Video Solution by SpreadTheMathLove== | ||
https://www.youtube.com/watch?v=EcrktBc8zrM | https://www.youtube.com/watch?v=EcrktBc8zrM | ||
| + | ==Video Solution by Interstigation== | ||
| + | https://youtu.be/1bA7fD7Lg54?t=113 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2023|num-b=2|num-a=4}} | {{AMC8 box|year=2023|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 20:37, 16 February 2023
Contents
Problem
Wind chill is a measure of how cold people feel when exposed to wind outside. A good estimate for wind chill can be found using this calculation
![\[(\text{wind chill}) = (\text{air temperature}) - 0.7 \times (\text{wind speed}),\]](http://latex.artofproblemsolving.com/6/6/8/66810c2843261301faabc4441239f8fa51b1f231.png)
where temperature is measured in degrees Fahrenheit 
and the wind speed is measured in miles per hour (mph). Suppose the air temperature is 
and the wind speed is 
mph. Which of the following is closest to the approximate wind chill?
Solution
By substitution, we have
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM
Video Solution by Magic Square
https://youtu.be/-N46BeEKaCQ?t=5606
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=EcrktBc8zrM
Video Solution by Interstigation
https://youtu.be/1bA7fD7Lg54?t=113
See Also
| 2023 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
