Difference between revisions of "2023 AMC 10A Problems/Problem 22"

Revision as of 21:41, 9 November 2023

Circle $C_1$ and $C_2$ each have radius $1$ , and the distance between their centers is $\frac{1}{2}$ . Circle $C_3$ is the largest circle internally tangent to both $C_1$ and $C_2$ . Circle $C_4$ is internally tangent to both $C_1$ and $C_2$ and externally tangent to $C_3$ . What is the radius of $C_4$ ?

$\textbf{(A) } \frac{1}{14} \qquad \textbf{(B) } \frac{1}{12} \qquad \textbf{(C) } \frac{1}{10} \qquad \textbf{(D) } \frac{3}{28} \qquad \textbf{(E) } \frac{1}{9}$

Solution

Connect the centers of $C_1$ and $C_4$ , and the centers of $C_3$ and $C_4$ . Let the radius of $C_4$ be $r$ . Then, from the auxillary lines, we get $(\frac{1}{4})^2 + (\frac{3}{4}+r)^2 = (1-r)^2$ . Solving, we get $r = \boxed{\frac{3}{28}}$

-andliu766

Video Solution 1 by OmegaLearn

https://youtu.be/jcHeJXs9Sdw

2023 AMC 10A (Problems • Answer Key • Resources)
Preceded by Problem 21	Followed by Problem 23
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 == Video Solution 1 by OmegaLearn ==
 https://youtu.be/jcHeJXs9Sdw
+==See Also==
+{{AMC10 box|year=2023|ab=A|num-b=21|num-a=23}}
+{{MAA Notice}}

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Difference between revisions of "2023 AMC 10A Problems/Problem 22"

Revision as of 21:41, 9 November 2023

Solution

Video Solution 1 by OmegaLearn

See Also