Difference between revisions of "2023 AMC 12A Problems/Problem 15"
(→Solution 1) |
m (→Solution 1) |
||
Line 13: | Line 13: | ||
<math>cos(\theta)=\frac{120}{100}</math> | <math>cos(\theta)=\frac{120}{100}</math> | ||
− | <math>\theta=\boxed{\textbf{(A) } cos^{-1}(\frac{5}{6})}</math> | + | <math>\theta=\boxed{\textbf{(A) } \cos^{-1}\left(\frac{5}{6})\right}</math> |
~lptoggled | ~lptoggled |
Revision as of 00:48, 10 November 2023
Question
Usain is walking for exercise by zigzagging across a -meter by -meter rectangular field, beginning at point and ending on the segment . He wants to increase the distance walked by zigzagging as shown in the figure below . What angle will produce in a length that is meters? (This figure is not drawn to scale. Do not assume that he zigzag path has exactly four segments as shown; there could be more or fewer.)
[someone add diagram]
Solution 1
By "unfolding" line into a straight line, we get a right angled triangle .
$\theta=\boxed{\textbf{(A) } \cos^{-1}\left(\frac{5}{6})\right}$ (Error compiling LaTeX. Unknown error_msg)
~lptoggled
Video Solution 1 by OmegaLearn
See also
2023 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 14 |
Followed by Problem 16 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.