Difference between revisions of "2005 AIME II Problems/Problem 14"
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== Problem == | == Problem == | ||
| − | In triangle <math> ABC, AB=13, BC=15, </math> and <math> | + | In triangle <math> ABC, AB=13, BC=15, </math> and <math>CA = 14. </math> Point <math> D </math> is on <math> \overline{BC} </math> with <math> CD=6. </math> Point <math> E </math> is on <math> \overline{BC} </math> such that <math> \angle BAE\cong \angle CAD. </math> Given that <math> BE=\frac pq </math> where <math> p </math> and <math> q </math> are relatively prime positive integers, find <math> q. </math> |
== Solution == | == Solution == | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=2005|n=II|num-b=13|num-a=15}} | |
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[[Category:Intermediate Geometry Problems]] | [[Category:Intermediate Geometry Problems]] | ||
Revision as of 12:07, 1 December 2007
Problem
In triangle 
and 
Point 
is on 
with 
Point 
is on such that 
Given that 
where 
and 
are relatively prime positive integers, find 
Solution
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See also
| 2005 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
