Difference between revisions of "2004 AMC 12A Problems/Problem 1"
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== Solution == | == Solution == | ||
<math>20</math> dollars is the same as <math>2000</math> cents, and <math>1.45\%</math> of <math>2000</math> is <math>0.0145\times2000=29</math> cents. <math>\Rightarrow\boxed{\mathrm{(E)}\ 29}</math>. | <math>20</math> dollars is the same as <math>2000</math> cents, and <math>1.45\%</math> of <math>2000</math> is <math>0.0145\times2000=29</math> cents. <math>\Rightarrow\boxed{\mathrm{(E)}\ 29}</math>. | ||
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| + | =Alternate Solution= | ||
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| + | Since there can't be decimal values of cents, the answer must be <math>\Rightarrow\boxed{\mathrm{(E)}\ 29}</math>. | ||
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| + | ~MathKatana | ||
== Video Solution == | == Video Solution == | ||
Latest revision as of 00:07, 20 March 2024
- The following problem is from both the 2004 AMC 12A #1 and 2004 AMC 10A #3, so both problems redirect to this page.
Problem
Alicia earns 20 dollars per hour, of which 
is deducted to pay local taxes. How many cents per hour of Alicia's wages are used to pay local taxes?
Solution
dollars is the same as 
cents, and of is 
cents. 
.
Alternate Solution
Since there can't be decimal values of cents, the answer must be .
~MathKatana
Video Solution
Education, the Study of Everything
See also
| 2004 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
