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Difference between revisions of "1957 AHSME Problems/Problem 13"

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We see that <math>A</math> and <math>B</math> are both irrational, so we look at <math>C</math>, <math>D</math>, and <math>E</math>.
 
We see that <math>A</math> and <math>B</math> are both irrational, so we look at <math>C</math>, <math>D</math>, and <math>E</math>.
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Recall that <math>\sqrt 2</math> is around <math>1.4</math>, and <math>\sqrt{3}</math> is around <math>1.7</math>
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Recall that <math>\sqrt 2</math> is around <math>1.4</math>, and <math>\sqrt{3}</math> is around <math>1.7</math>.
 
The only number between these is <math>\boxed{\textbf{(C) }1.5}</math>.
 
The only number between these is <math>\boxed{\textbf{(C) }1.5}</math>.
  

Latest revision as of 08:20, 25 July 2024

Problem

A rational number between $\sqrt{2}$ and $\sqrt{3}$ is:

$\textbf{(A)}\ \frac{\sqrt{2} + \sqrt{3}}{2} \qquad \textbf{(B)}\ \frac{\sqrt{2} \cdot \sqrt{3}}{2}\qquad \textbf{(C)}\ 1.5\qquad \textbf{(D)}\ 1.8\qquad \textbf{(E)}\ 1.4$

Solution

We see that $A$ and $B$ are both irrational, so we look at $C$, $D$, and $E$. Recall that $\sqrt 2$ is around $1.4$, and $\sqrt{3}$ is around $1.7$. The only number between these is $\boxed{\textbf{(C) }1.5}$.

~JustinLee2017

See Also

1957 AHSC (Problems • Answer Key • Resources)
Preceded by
Problem 12 		Followed by
Problem 14
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All AHSME Problems and Solutions

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