Difference between revisions of "2014 AMC 8 Problems/Problem 1"
m (→SOLUTION 2) |
m (→Solution) |
||
Line 10: | Line 10: | ||
− | == | + | ==Solution== PEMDAS |
We use PEMDAS, 8-(2+5) is the same as 8-7 which is 1, 8-2+5 is the same as 6+5 because 8-2 comes first, and the sum is 11. H-T is 1-11 which is <math>\boxed{\textbf{(A)}-10}</math>. | We use PEMDAS, 8-(2+5) is the same as 8-7 which is 1, 8-2+5 is the same as 6+5 because 8-2 comes first, and the sum is 11. H-T is 1-11 which is <math>\boxed{\textbf{(A)}-10}</math>. |
Revision as of 00:56, 15 September 2024
Problem
Harry and Terry are each told to calculate . Harry gets the correct answer. Terry ignores the parentheses and calculates . If Harry's answer is and Terry's answer is , what is ?
Solution
We have and . Clearly , so our answer is .
==Solution== PEMDAS
We use PEMDAS, 8-(2+5) is the same as 8-7 which is 1, 8-2+5 is the same as 6+5 because 8-2 comes first, and the sum is 11. H-T is 1-11 which is .
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.