2014 AMC 10A Problems/Problem 15

The following problem is from both the 2014 AMC 12A #11 and 2014 AMC 10A #15, so both problems redirect to this page.

Problem

David drives from his home to the airport to catch a flight. He drives miles in the first hour, but realizes that he will be hour late if he continues at this speed. He increases his speed by miles per hour for the rest of the way to the airport and arrives minutes early. How many miles is the airport from his home?

Solution 1

Note that he drives at miles per hour after the first hour and continues doing so until he arrives.

Let be the distance still needed to travel after hour. We have that , where the comes from hour late decreased to hours early.

Simplifying gives , or .

Now, we must add an extra miles traveled in the first hour, giving a total of miles.

Solution 2 (Answer Choices)

Instead of spending time thinking about how one can set up an equation to solve the problem, one can simply start checking the answer choices. Quickly checking, we know that neither choice or choice work, but does. We can verify as follows. After hour at , David has miles left. This then takes him hours at . But . Since is hours less than , our answer is .

Solution 3

Let the total distance be , and let the time taken after the speed change be . Then . Since 1 hour has passed, and he increased his speed by miles per hour, and he had already traveled miles, the new equation is . Solving, , , , and .

~JH. L

Video Solutions

i) (https://youtu.be/FyOhLdpeBLM?si=OY741QZ_WKpPMSDN) [By WhyMath]

ii) (https://youtu.be/UcE9-Hc3S9s?si=cuR-qhCD4Kn3D3sJ) [By Forbest Academy]

iii) (https://youtu.be/eO6j_BQDyA4?si=mZg3B9pnqVjYfiP1) [By Ashley Shen (in Chinese)]

~helloall35AAD

See Also

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.